**Material Estimation for Concrete:**

In this article we will discuss the estimation of material for concrete in which we will find the quantities of materials for concrete such as cement, fine aggregate and aggregates for production of required quantity of concrete of a mix proportions like 1:2:4, 1:1.5: 3, 1:1:2 can be calculated by two methods:

The RCC (Reinforced Cement Concrete) consist of beams, slabs, columns and foundations etc. based on classification of structure. The volume of concrete need for concrete structure can be find by adding the volumes of each structural member or each parts of members.

The volume of a rectangular or square member can be find as length x Breadth x height (thickness). proper formula shall be used for different shapes of members.

For the estimation of materials for concrete following materials will be calculate that is given below:

- W =Mass of water
- C = Mass of cement
- Fa = Mass of fine aggregates
- Ca = Mass of coarse aggregates

The air content has been ignored in the calculation.

**Methods for the estimation of concrete materials:**

There are two methods for the estimation of materials for concrete.

- 1
^{st}Method - 2
^{nd}

**1**^{st} Method:

^{st}Method:

There are few steps for the estimation of materials for concrete these steps are given below:

- Wet Volume of structure
- Convert wet volume into dry
- Quantity of cement
- Quantity of sand
- Quantity of coarse aggregate
- Quantity of water

To calculate the materials for concrete let’s take an example

**Example:**

A slab having length 10m breadth 5m and thickness or depth 0.125m. the water cement ratio is 0.50 find the materials for concrete M15 (1:2:4)?

**Wet volume of structure:**

First step is to find the volume of structure or member

Volume = Length × Breadth × Thickness

Volume = 10 × 5 × 0.125

Volume = 6.25 m^{3}

**Convert Wet Volume into Dry:**

To find the dry volume simply multiply the wet volume with the value that is “1.54” it will convert into dry volume.

Wet volume = 6.25 m^{3}

To convert wet volume into dry volume

Dry volume = 6.25 × 1.54

Dry Volume = 9.625 m^{3}

**Quantity of Cement:**

To find the quantity of cement the following steps should be used that is given below:

- Sum of concrete ratio or proportion
- Density of cement

We find the quantity of cement for the M15 concrete in which ratio of this concrete is **1:2:4** so “**1”** is the **cement** “2” is the sand while “4” is the coarse aggregate.

**sum of the concrete ratio = 1+2+4**

**sum of the concrete ratio = 7**

Density of cement is 1440 kg/m^{3}

**Cement Quantity = (Cement Part / sum of ratio)** **× Dry Volume** **× cement Density **

**Cement Quantity = (1 / 7)** **× 9.625** **×1440**

**Cement Quantity = 1980 kg**

To convert kilogram into bags simply divide the kilogram by 50 because 1 bag cement contains 50 kilograms.

**Cement Quantity = 1980/50**

**Cement Quantity = 39.6 say 40 bags**

**Quantity of Sand:**

The quantity of sand can have calculated as the method for the estimation of the quantity of sand is given below:

We find the quantity of sand for the M15 concrete in which ratio of this concrete is **1:2:4** so “1**”** is the cement “**2**” is the **sand** while “4” is the coarse aggregate.

**sum of the concrete ratio = 1+2+4**

**sum of the concrete ratio = 7**

**Quantity of Sand = (Sand Part / sum of ratio)** **× Dry Volume **

**Quantity of Sand = (2 / 7)** **× 9.625**

**Quantity of Sand = 2.75 m ^{3}**

**Quantity of Coarse Aggregate:**

The estimation of the quantity of coarse aggregate is given below:

We find the quantity of coarse aggregate for the M15 concrete in which ratio of this concrete is **1:2:4** so “1**”** is the cement “2” is the sand while “**4**” is the **coarse aggregate**.

**sum of the concrete ratio = 1+2+4**

**sum of the concrete ratio = 7**

**Quantity of Coarse Aggregate = (coarse aggregate Part / sum of ratio)** **× Dry Volume **

**Quantity of Sand = (4 / 7)** **× 9.625**

**Quantity of Sand = 5.5 m ^{3}**

**Water Cement Ratio:**

If water cement is not given by designer, we can assume the water cement ratio According to IS 10262 (2009). Here the value of water cement ratio is 0.50

**Required Amount of Water = W/C Ratio X weight of Cement(kg)**

**Weight of cement = No. of bags x 50**

Where 1 bag of cement contain 50 kg cement

**Weight of cement = 40 x 50**

**Weight of cement = 2000**

**Required Amount of Water** **= 0.50 X 2000**

**Required Amount of Water = 1000 liters**

**2**^{nd} Method:

^{nd}Method:

- Volume of structure
- Multiply value of table with volume

S.No |
Concrete Mix |
Cement |
Sand(m^{3}) |
Coarse Aggregate (m^{3}) |
||

cubic meter(m^{3}) |
Number of Bags |
By weight(Kg) |
||||

1 | 1:6:12 | 0.08 | 2.2 | 110 | 0.48 | 0.95 |

2 | 1:5:10 | 0.09 | 2.6 | 130 | 0.47 | 0.94 |

3 | 1:4:8 | 0.12 | 3.4 | 170 | 0.46 | 0.91 |

4 | 1:3:6 | 0.15 | 4.4 | 220 | 0.45 | 0.91 |

5 | 1:2.5:5 | 0.18 | 5.2 | 260 | 0.45 | 0.89 |

6 | 1:2:4 | 0.22 | 6.4 | 320 | 0.44 | 0.87 |

7 | 1:1.5:3 | 0.28 | 8 | 400 | 0.42 | 0.84 |

8 | 1:1:02 | 0.39 | 11.2 | 560 | 0.39 | 0.78 |

To calculate the materials for concrete let’s take an example

**Example**:

A beam having length 10 m breadth 0.3 m and thickness or depth 0.5m. the water cement ratio is 0.50 find the materials for concrete M15 (1:2:4)?

**Quantity of Cement:**

To find the quantity of cement the following steps should be used that is given below:

- Find Volume of the structural member
- Select value for concrete Mix
- Multiply Selected Value of concrete mix with Volume

**Volume = Length × Breadth × Thickness**

**Volume = 10 × 0.3 × 0.5**

**Volume = 1.5 m3**

We find the quantity of cement for the M15 concrete in which table value for cement is given for Kilogram, cubic meter (m^{3}) and in bags. It means that we can find find the quantity of cement either in kilogram, cubic meter (m^{3}) and also in bags just multiply the value volume with the table values.

**Cement Quantity in Kilogram:**

Cement can find in kilogram just multiply the table value with volume

**Cement Quantity = value of table** **× Volume**

**Cement Quantity = 320** **× 1.5**

**Cement Quantity = 480 kg**

**Cement Quantity in Bags:**

Cement can find in bags just multiply the table value with volume

**Cement Quantity = value of table** **× Volume**

**Cement Quantity = 6.4** **× 1.5**

**Cement Quantity = 9.6 bags**

**Cement Quantity in volume(m ^{3}):**

Cement can find in volume (m^{3}) just multiply the table value with volume the of structural member.

**Cement Quantity = value of table** **× Volume**

**Cement Quantity = 0.22** **× 1.5**

**Cement Quantity = 0.33 (m ^{3})**

To convert kilogram into bags simply divide the kilogram by 50 because 1 bag cement contains 50 kilograms.

**Cement Quantity = 1980/50**

**Cement Quantity = 39.6 say 40 bags**

**Quantity of Sand (m**^{3}):

^{3}):

Sand can find in volume (m^{3}) just multiply the table value with volume the of structural member.

**Quantity of Sand = value of table** **× Volume**

**Quantity of Sand = 0.44** **× 1.5**

**Quantity of Sand = 0.66 (m ^{3})**

The quantity of sand can have calculated as the method for the estimation of the quantity of sand is given below:

We find the quantity of sand for the M15 concrete in which ratio of this concrete is **1:2:4** so “1**”** is the cement “**2**” is the **sand** while “4” is the coarse aggregate.

**sum of the concrete ratio = 1+2+4**

**sum of the concrete ratio = 7**

**Quantity of Sand = (Sand Part / sum of ratio)** **× Dry Volume **

**Quantity of Sand = (2 / 7)** **× 9.625**

**Quantity of Sand = 2.75 m ^{3}**

**Quantity of Coarse Aggregate:**

Coarse aggregate can find in volume (m^{3}) just multiply the table value with volume the of structural member.

**Quantity of Coarse Aggregate = value of table** **× Volume**

**Quantity of Coarse Aggregate = 0.88** **× 1.5**

**Quantity of Coarse Aggregate = 1.32 (m ^{3})**

**Water Cement Ratio:**

If water cement is not given by designer, we can assume the water cement ratio According to IS 10262 (2009). Here the value of water cement ratio is 0.50

**Required Amount of Water = W/C Ratio X weight of Cement(kg)**

**Required Amount of Water** **= 0.50 X 480**

**Required Amount of Water = 240 liters**

**Note:**

If you want to calculate the quantity of material and the dimension is given in foot or inches etc. simply convert these units **(unit conversion**) in meter and then calculate the materials in these methods which I have discuss in this article.

**You may also read:**

- Types of Concrete and their Uses, Classification and Properties
- Standard Size of Column
- Difference Between Short Column and Long Column